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(a + b)2 = a2 + 2ab + b2 (a – b)2 = a2 – 2ab + b2 (a + b) (a – b) = a2 – b2 (x + a) (x + b) = x2 + (a + b)x + ab. (x + a) (x – b) = x2 + (a – b)x – ab. (x – a) (x + b) = x2 + (b – a)x – ab. (x – a) (x – b) = x2 – (a + b)x + ab. (a + b)3 = a3 + b3 + 3ab(a + b)

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Rachana H 5 years, 4 months ago

Geometry Shapes Formulas for 2D Shapes: Geometric AreaGeometric Area FormulaSquarea2Rectanglea × bCircleπr2Ellipseπr1r2Triangle½(b × h) Algebra Formulas for Class 8 Algebraic Identities For Class 8(a + b)2 = a2 + 2ab + b2(a − b)2 = a2 − 2ab + b2(a + b) (a – b) = a2 – b2(x + a) (x + b) = x2 + (a + b)x + ab(x + a) (x – b) = x2 + (a – b)x – ab(x – a) (x + b) = x2 + (b – a)x – ab(x – a) (x – b) = x2 – (a + b)x + ab(a + b)3 = a3 + b3 + 3ab (a + b)(a – b)3 = a3 – b3 – 3ab (a – b)

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construct a quadrilateral HAIR in which HA=4cm AI=5.5cm angle H=60° angle A =105° and angle R =75°

Posted by Jatin Thakur 5 years, 4 months ago

CBSE > Class 08 > Mathematics

3 answers

Diksha Laniya🐥 5 years, 4 months ago

ANSWER We have, HE=6cm. EL=4.5cm. ∠H=60o ∠E=105o ∠P=120o We shall find the fourth angle first. Sum of all the angles of a quadrilateral=360o ∴∠L=360o=(60o+105o+120o) ∠L=750o Step (1):-first draw base HE=6cm. Step (2):- Construct ∠H=60o Step (3):- Construct ∠E=105o On this line of ∠E cut an arc at 4.5 cm. Step(4):- Construct ∠L=75o Complete figure.

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Diksha Laniya🐥 5 years, 4 months ago

Hello jatin thakur can help me on subject maths chapter 7 exercise 7.2and7.3 please help me send me answers is whatappno. Our cbse guide

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Diksha Laniya🐥 5 years, 4 months ago

Hello can help me on subject maths chapter 7 exercise 7.2and7.3 please help me

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ANSWER

5(y-1)=3(2y-5)-(1-3y)

Posted by Maku Sarmah 5 years, 4 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years, 4 months ago

5(y-1)=3(2y-5)-(1-3y)

5y - 5 = 3(2y) - 3 (5) - 1 + 3y

5y - 5 = 6y - 15 - 1 + 3y

5y - 5 = 9y - 16

5y - 9y = - 16 + 5

- 4y = - 11

y = 11/4

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9-2(x-5)=x+10 9-2x+10=x+10 -2x+19=x+10 -2x-x=10-19 -3x=-9 X=9/3=3 Is it right or wrong answer please reply me

Posted by Maku Sarmah 5 years, 4 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

9-2( x-5)=x+10

Posted by Maku Sarmah 5 years, 4 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years, 4 months ago

9-2( x-5)=x+10

9 - 2x + 10 = x + 10

-2x + 19 = x + 10

-2x - x = 10 - 19

-3x = - 9

x = 9/3 = 3

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ANSWER

Define rational numbers and example also

Posted by Shivangi Modanwal 5 years, 4 months ago

CBSE > Class 08 > Mathematics

2 answers

Shivangi Modanwal 5 years, 4 months ago

Thanks❤❤

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Yogita Ingle 5 years, 4 months ago

A rational number, in Mathematics, can be defined as any number which can be represented in the form of p/q where q ≠ 0. Also, we can say that any fraction fits under the category of rational numbers, where the denominator and numerator are integers and the denominator is not equal to zero. When the rational number (i.e., fraction) is divided, the result will be in decimal form, which may be either terminating decimal or the repeating decimal.

Example: 12/17, 9/11 and 3/5 are positive rational numbers

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Definition of triangle square rectangles, rombhus and what is diagonal

Posted by Shivangi Modanwal 5 years, 4 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years, 4 months ago

A Rectangle is a four sided-polygon, having all the internal angles equal to 90 degrees. The two sides at each corner or vertex, meet at right angles. The opposite sides of the rectangle are equal in length which makes it different from a square.
Square is a quadrilateral in which all its sides have equal length and all the four corners are right angles.
A diagonal is a line segment connecting two non-consecutive vertices of a polygon.

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ANSWER

Tell me peremetre of square, triangle, rectangle and area

Posted by Shivangi Modanwal 5 years, 4 months ago

CBSE > Class 08 > Mathematics

2 answers

Divyansh Jain 5 years, 4 months ago

Perimeter of square = 4 × side Area of square = Side × Side Perimeter of triangle = 3 × side Area of Triangle = 1/2 × base × height Perimeter of rectangle = 2 ( Length + Breadth ) Area of Rectangle = Length × Breadth

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Yogita Ingle 5 years, 4 months ago

peremetre of square = 4 side

area of square = side × side

Perimeter of triangle = addition of three sides of triangle

Area of trianlge = 1/2 × base × height

Perimeter of rectanlge = 2L + 2B

area of rectangle = length × breadth

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write the addictive inverse of -19/6

Posted by Rajat Singh Tomar 5 years, 4 months ago

CBSE > Class 08 > Mathematics

2 answers

Divyansh Jain 5 years, 4 months ago

The additive inverse of -19/6 = 19/6

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Avani Rana 5 years, 4 months ago

19/6

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ANSWER

Find the coefficient of xyz in . 3/2x + y - z - xyz/5

Posted by Harmeet Kaur 5 years, 4 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

A car take 2 hours to reach the destination

Posted by Sparsh Mishra 5 years, 4 months ago

CBSE > Class 08 > Mathematics

2 answers

Zibiah Gonsalves 5 years, 4 months ago

Therefore the car faced traffic

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Divyansh Jain 5 years, 4 months ago

Please write the full question

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ANSWER

At what rate of compound interest per annum will Rs.1250 Amount to Rs.1800 in 2 years?

Posted by Sanjana Ghanta 5 years, 4 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 5 years, 4 months ago

Here is your answer...
Given is Time = 2 years
Amount=₹1800
Principal = ₹1250
Rate = ?
The formula to calculate amount is
=A = P(1 + R/100)^T
=1800 = 1250 × (1+ R/100)²
=1800/1250 = (1+ R/100)²
=√(36/25) = 1+ R/100
=6/5 - 1 = R/100
=1/5 × 100 = R
=20 = R
Therefore, the rate is 20%.

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The tens digit in a two digit number is twice the units digit if 18 is subtracted from the number the digits are reversed find the number

Posted by Aniket Chaudhary 5 years, 4 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

Rahul sold a watch to sohan at a gain of 10%and sohan sold it to at a loss of 10% .If mohan paid ₹990for it,find the price paid by rahul

Posted by Sakshi Thakur 5 years, 4 months ago

CBSE > Class 08 > Mathematics

1 answers

Avani Rana 5 years, 4 months ago

Let the CP is given by Rahul be x. Gain% = 10% SP = CP(_100 + gain%_)/100 SP = x( 100+ 10)/100 SP = 110x/ 100 According to question, SP of Rahul = CP of Sohan Then, CP of Sohan = 110x/ 100 Loss%= 10% SP = CP(100 - loss%)/100 = 110x / 100( 100 - 10)/100 = 110x / 100 * 90/ 100 99x/100 According to question, CP of Sohan = CP of Mohan CP of Mohan = 99x/100 Also Mohan paid for it Rupees 990 Therefore, 99x/ 100 = 990 x= 990*100/99 x= Rs 1000 So Rahul paid for the watch is Rs 1000. Hope it helps u....

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Evaluate each of the following using identities: (4x+5y) (4x+5y)

Posted by Armaan Jadeja 5 years, 4 months ago

CBSE > Class 08 > Mathematics