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find the value of k for which point (1,-2) lies on the graph of linear eq x-2y+k=0

Posted by Savitajain Jain 8 years, 11 months ago

CBSE > Class 09 > Mathematics

1 answers

Sudhanshu Yadav 8 years, 11 months ago

Given: point (1,-2) lies on on the graph of linear equation = x-2y+k=0

Put x=1 ,y=-2 in the given equation.

So, 1-2(-2)+k=0

1+4+k=0

5+k=0

K=-5

-------------------

Value of k= -5.

0Thank You

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