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(SinA+cosecA)² +(cosA+secA)²=7+tan²A+cot²A

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(SinA+cosecA)² +(cosA+secA)²=7+tan²A+cot²A

    • Posted by Kartik Chauhan 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Tanya Chauhan 4 months, 3 weeks ago

    Very simple. LHS (Sin^2 A + cosec^2 A + 2 sin A cosec A)+( cos^2A+sec^2A +2cosA secA) (Sin^2A+cosec^2A+2)+ ( cos^2A+sec^2A+2) (Sin^2A +cos ^2A) +4+(cosec^2A+sec^2A) 1+4+(1+cot ^2A) +( 1+tan^A) (7+tan ^2A+cot^2A) = RHS

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