Lavanya throws a ball upwards, from …
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Lavanya throws a ball upwards, from a rooftop, which is 20 m
above from ground. It will reach a maximum
height and then fall back to the ground. The height of the ball
from the ground at time t is h , which is given by
h=-4t2+16t+20 .
(i)What is the height reached by the ball after 1 second?
(II)What is the maximum height reached by the ball
(iii) How long will the ball take to hit the ground?
(iv) What are the two possible times to reach the ball at
the same height of 32 m?
(v) Where is the ball after 5 seconds ?
Posted by Nivritee Pal 5 months, 1 week ago
- 0 answers
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