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Starting from rest a scooter acquires …

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Starting from rest a scooter acquires a velocity of 36 km per hour in 10 seconds and then brakes are applied it takes 25 seconds to stop find out the acceleration and distance travelled during this motion
  • 2 answers

Mohd Rihan 1 week, 6 days ago

Find out the story be hind the discovery of nuclear and protoplasm and write it in brief

Kushagra Goyal 2 weeks, 3 days ago

Case I Initial velocity (u)=0m/s Final velocity (v)= 36km/h=36×5/18= 10m/s [1km/h=5/18 m/s] Time= 20 sec Acceleration=? By using first equation of motion [V=u+at] 36 =0 + a×20 36 - 0 = 20a 36/20 =a 9/5 = a 1.8m/s² Case II Initial velocity (u)=36km/h= 36×5/18= 10m/s [1km/h=5/18 m/s] Final velocity (v)= 0m/s Time= 25 sec Acceleration=? By using first equation of motion [V=u+at] 0= 36 + a×25 0-36=25a -36/25=a 1.44m/s² Case I Initial velocity (u)=0m/s Final velocity (v)= 36km/h=36×5/18= 10m/s [1km/h=5/18 m/s] Time= 20 sec Acceleration=1.8m/s² Distance=? By using second equation of motion [s=ut+½at²] 0×20+½×1.8×20² =360m Case II Initial velocity (u)=36km/h= 36×5/18= 10m/s [1km/h=5/18 m/s] Final velocity (v)= 0m/s Time= 25 sec Acceleration=1.44m/s² Distance=? By using second equation of motion [s=ut+½at²] 10×25+½1.44×25² =700m
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