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Equivalent resistance of two resistors in …

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Equivalent resistance of two resistors in series is 90 ohm. If R1= 5 ohm then find R2. Calculate the equivalent resistance when two are connected in parallel

Posted by Sanya Gupta 8 months, 3 weeks ago

CBSE > Class 10 > Science

2 answers

T Koushik 8 months, 3 weeks ago

In series Rs=R1+R2+R3..... Given, R1=5ohm Rs=90ohm therefore, R1+R2=90 5+R2=90 R2=85ohm ATP: In parallel 1/Rp=1/R1+1/R2... 1/Rp=1/5+1/85 1/Rp=7+1/85 1/Rp=8/85 Rp=85/8 Rp=10.6ohm

2Thank You

Diksha Gupta 8 months, 3 weeks ago

R2 = 85 ohm When connected in parallel Equivalent resistance = 5 ohm

1Thank You

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Posted by Nitish Kumar Yadav 1 month, 3 weeks ago

CBSE > Class 10 > Science