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Sin 30 +tan45/sec30 + cot45

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Sin 30 +tan45/sec30 + cot45

    • Posted by Siju Divy 9 months, 1 week ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Ritika Chauhan 9 months, 1 week ago

    Solution - Sin30° = 1/2 , tan 45° = 1 , sec 30° = 2/√3 , cot45° = 1 = 1/2 + 1 ÷ √3/2 + 1 = 1+2 / 2 ÷ √3 + 2 / 2 = 3 / 2 × 2 / √3 + 2 = 3 / √3 + 2 = √3 × √3 / √3 + 2 = √3 / 2 = Sin 60° answer I hope this is helpful to you...~

    1Thank You

    Kavya Rajvanshi 9 months, 1 week ago

    1/2+1÷ 2/√3+1 = 1+2/3 ÷ 2+√3/2√3 = 3√3(2-√3)/2 is a answer

    0Thank You

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