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द एंगल ऑफ़ एलिवेशन ऑफ़ द …

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द एंगल ऑफ़ एलिवेशन ऑफ़ द टॉप ऑफ़ ए बिल्डिंग फ्रॉम थे फुट का थे टावर इस 30° एंड द एंगल ऑफ़ एलिवेशन ऑफ़ द टॉप ऑफ़ द टावर फ्रॉम थे फुट ऑफ़ द बिल्डिंग 60° आईएफ थे टावर इस 50 एम हाई फाइंड द हाइट ऑफ़ द बिल्डिंग

    • Posted by Rehan Nawaj 9 months, 2 weeks ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Gourav Sharma 9 months, 2 weeks ago

    Height of the tower is 50 meter and Angle is 60degree Tan60 is perpendicular/base Tan60 is √3 And let the base be x √3 = 50/x By cross multiplication √3x=50 X=50/√3 So base is 50/√3 Now let the height of the building be x Tan30=perpendicular/base Tan30=1/√3 1/√3=x/50/√3 1/√3×√3=x/50 3×50=x X=150 Height of the building is 150meter

    0Thank You

    Gourav Sharma 9 months, 2 weeks ago

    Height of the tower=50meter

    1Thank You

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