Height of a solid cylinder is …

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Given: Height of cylinder(H) = 10cm Diameter of base of cylinder = 8cm Therefore, Radius of the cylinder(R) = (8/2)cm = 4cm Height of conical holes, made on both the ends of cylinder(h) = 4cm Diameter of conical holes = 6cm Therefore, Radius of conical holes(r) = (6/2)cm = 3cm Slant height of conical holes(l) = (h² + r²)^1/2 = {(4)² + (3)²}^1/2 = (16 + 9)^1/2 = (25)^1/2 = 5cm To find: i) T.S.A. of cylinder. ii) T.S.A. of remaining solid. Solution: i) T.S.A. of cylinder = 2 × (22/7) × R × (R + H) = 2 × (22/7) × 4 × (4 + 10) = 352 cm² ii) T.S.A. of remaining solid = { (T.S.A. of cylinder) - 2(Base area of conical hole) } + { 2(C.S.A. of conical hole) } = [ { 352 } - 2{ (22/7) × r² } ] + [ 2{ (22/7) × r × l } ] = { 352 - (396/7) } + { (660/7) } = (2464 + 660 - 396)/7 = 390 cm² (approximately)