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Through the mid-point M of the …

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Through the mid-point M of the side CD of a parallelogram ABCD, the line BM is drawn intersecting AC at L. and AD produced to E. prove that EL = 2BL.

    • Posted by Chetan Jha 10 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Vishal Dubay 9 months, 2 weeks ago

    In △BMC and △EMD ∠BMC=∠EMD [Vertically opposite] MC=DM [Given] ∠BCM=∠EDM [Alternate angles] ∴△BMC≅△EMD [By ASA] Hence, BC=DE [By CPCT] →(1) AE=AD+DE=BC+BC=2BC →(2) Now, △BLC∼△ELA (AA Similarly) BLEL=BCAE [By CPCT] BLEL=BC2BC BLEL=12 EL=2BL 

    1Thank You

    Chetan Jha 10 months ago

    In △BMC and △EMD ∠BMC=∠EMD [Vertically opposite] MC=DM [Given] ∠BCM=∠EDM [Alternate angles] ∴△BMC≅△EMD [By ASA] Hence, BC=DE [By CPCT] →(1) AE=AD+DE=BC+BC=2BC →(2) Now, △BLC∼△ELA (AA Similarly) BLEL=BCAE [By CPCT] BLEL=BC2BC BLEL=12 EL=2BL 

    0Thank You

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