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The floor of a building consist of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length find the total cost of polishing the floor , if cost per metre square is rupees 4

Posted by Deva Prabha S 3 months, 3 weeks ago

CBSE > Class 08 > Mathematics

1 answers

Pratigya Pandey 3 months, 3 weeks ago

Area o tile (rhombus) = ½×product of diagonals = ½ × 45cm × 30 cm = 675cm² = 675 × 1/10000m² = Area of 3000 tiles = 675 × 1/10000 × 3000 = 2025/10m² = 202.5m² =Cost of polishing of 1m² area = Rs.4 = Cost of polishing of 202.5m² area = Rs.4 × 202.5 = Rs.810

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