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Find to consecutive positive integers sum …

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Find to consecutive positive integers sum of whose squares is 421
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Kaushik Verma 10 months, 2 weeks ago

x²+(x+1)²=421 x²+x²+1+2x=421 2x²+2x=420 2x²+2x-420=0 2(x²+x-210)=0 x²+x-210=0 D=b²-4ac =1²-4×1×(-210) =1+840 =841 underoot841=29 x=14 x=-15(it is neglected)
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