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Find the point on the y-axis …

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Find the point on the y-axis which is equidistant from the point (6,5)and(-4,3)

    • Posted by Aryan Chaurasiya 10 months, 3 weeks ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Bhupendra Kumar Singh 10 months, 3 weeks ago

    √(0-6)^2+(5-y)^2=√(-4-0)^2+(3-y)^2 =>36+25+y^2-10y=16+9+y^2-6y=>61+y^2-10y=25+y^2-6y=>36-4y=0........y=9..... required coordinates are (0,9)

    0Thank You

    Abhishek Kumar Ranjan 10 months, 3 weeks ago

    => cood.of y=(0,y) . => Cood.of y=(-4+6/2 , 3+5/2). =( 1,4) On comparing, (1=0, 4=y) Cood.of y=(0,4)

    0Thank You

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