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Find the nature of roots of …

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Find the nature of roots of root3xsquare-root7x+3root3
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In this case, a = √3, b = -√7, and c = 3√3. Substituting these values in the formula, we get: b² - 4ac = (-√7)² - 4(√3)(3√3) = 7 - 36 = -29 < 0 So, there are no real roots for the given equation
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