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# Find the 11th term of the …

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Find the 11th term of the AP (5a-x), 6a, (7a+x)
• 2 answers

Suryesh Kumar 4 months ago

Given , AP=(5a-x),(6a),(7a+x) Here , A = 5a-x T¹=5a-x , T ²=6a, T³=7a+ x, D = T²-T¹ => D = 6a - (5a-x) => D= 6a - 5a+ x => D = a + x Now , T ^n = A+ (n-1)D => T ¹¹= A + (11-1)D => T ¹¹ = (5a-x) +10 (a+x) => T ¹¹ = 5a-x + 10a + 10x => T ¹¹ = 10a + 5a +10x - x => T ¹¹ = 15a + 9x Hence the 11th term of this AP is 15a + 9x

Shubhank Mittal 4 months ago

Given, a=( 5a-x) d=a2-a1 6a-(5a-x) 6a-5a+x a+x an =a+(n-1)d a11= 5a-x+(11-1)a+x 5a-x+(10) a+x 5a-x+ 10a +10x 15a+9x answer

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