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the perimeter of an isosceles triangle …

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the perimeter of an isosceles triangle is 32cm the ratio of the equal sides to its base is 3:2 find the area of the triangle

    • Posted by Chinmay M.R 7 months, 3 weeks ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Shourya Deep 7 months, 3 weeks ago

    Let the equal side be 'a' and base be 'b', then its perimeter = 2a + b Let 'a' be 3k and 'b' be 2k. A/Q Perimeter = 32cm. ⇒2×3k + 2k = 32cm ⇒8k = 32cm ⇒k= 4cm. Hence, sides of triangles are 12cm, 12cm and 8cm. a=12 cm b=8cm Now, area of isosceles triangle= (b/4) × √(4a²–b²) = 2× √(4×144–64) = 2× √(576–64) = 2× √(512) =2× 16√2 =32√2 Hence, area of triangle is 32√2cm².

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