No products in the cart.

the perimeter of an isosceles triangle …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

the perimeter of an isosceles triangle is 32cm the ratio of the equal sides to its base is 3:2 find the area of the triangle
  • 1 answers

Shourya Deep 4 months, 1 week ago

Let the equal side be 'a' and base be 'b', then its perimeter = 2a + b Let 'a' be 3k and 'b' be 2k. A/Q Perimeter = 32cm. ⇒2×3k + 2k = 32cm ⇒8k = 32cm ⇒k= 4cm. Hence, sides of triangles are 12cm, 12cm and 8cm. a=12 cm b=8cm Now, area of isosceles triangle= (b/4) × √(4a²–b²) = 2× √(4×144–64) = 2× √(576–64) = 2× √(512) =2× 16√2 =32√2 Hence, area of triangle is 32√2cm².
http://mycbseguide.com/examin8/

Related Questions

Write 8 rational number between 13&15
  • 0 answers
(3+root3) (3-root3
  • 0 answers
0.12333....p/q form
  • 2 answers
Simplify √3-²
  • 0 answers
What number rational between34
  • 1 answers
2x^2-4x-2
  • 1 answers
Mathematics homework help me
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App