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A battery of 9v is connected …

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A battery of 9v is connected in series with resistors of 0.2Ω,0.3Ω,0.4Ω,0.5Ω and 12Ω respectively how much current would flow through the 12Ω resistor

Posted by Sneha Agarwal 1 year, 1 month ago

CBSE > Class 10 > Science

2 answers

Mayank Bharadwaj 1 year, 1 month ago

By formula v=ir 9=i×12 9÷12=I 3/4=i

0Thank You

Jeeva Dharshini 1 year, 1 month ago

Rs=13.4ohm I=V/R I=9×10/13.4×10 I=90/134 I=0.67A

3Thank You

ANSWER

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CBSE > Class 10 > Science