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if the polynomial p(x)=x3+8x2+17x+ax is divided …

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if the polynomial p(x)=x3+8x2+17x+ax is divided by (x+2) and (x+1) the remainders are same find the value of a.

  • 1 answers

Naveen Sharma 8 years, 11 months ago

p(x)=x3+8x2+17x+ax

As the remainder same in both case :

then p(-2) = p(-1)

(-2)3+ 8(-2)+ 17(-2) + a(-2)  = (-1)+ 8(-1)2 + 17(-1) + a(-1)

=> -8 + 32 - 34 - 2a = -1 + 8 - 17 - a

=> -10  -2a = - 10 - a

=> -2a + a = -10 + 10

=> -a = 0

=> a = 0

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