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The kepler's law period: T²=kx³, the …

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The kepler's law period: T²=kx³, the constant k=10`³ s²m`³. Express the constant k in days and kilometre. The moon is at a distance of 3.84×10⁵km from earth obtain it's time-period of revolution in days???

    • Posted by Tanishq Maheshwari 1 year, 2 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 1 year, 2 months ago

    1 day corresponds to (24×60×60) seconds and 1 km to 1000 m. Therefore, 10^-3 s^2 / m^3 corresponds to 10^-3 × (10^3)^3 day^2 / (24 × 60 × 60)^2 km^3 = 10^6 / 7.46 × 10^9 = 10 × 10^-4 / 7.46 = 1.34 × 10^-4 day^2 / km^3 //

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