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In ∆ABC, right angled at B, …

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In ∆ABC, right angled at B, AB = 24 CM, BC = 7 CM. Determine : (I) sin A, cos A

Posted by Monishka Kumawat 1 year, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Ishant Singh 1 year, 2 months ago

Sin=7/25& cos=24/25

Govind B 1 year, 2 months ago

Ans. Given : in triangle ABC , right angle at B , AB=24cm and BC=7cm To find: sinA and cos A Now by Pythagoras AC² =AB²+BC² AC² =(24)²+(7)² AC = √576+49 AC =√625 AC =√(25)² AC =25cm We have AC =25 Now SinA=perpendicular/ hypothesis SinA = BC/AC therefore, SinA= 7/25 Now Similarly, CosA =base/ hypothesis CosA = AB/AC CosA = 24/25 Hence, sinA =7/25 CosA =24/25

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