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Vector A= 3i-4j+5k Vector B= -2i+j+3k

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Vector A= 3i-4j+5k Vector B= -2i+j+3k

Posted by Prachi Kharanshu 1 year, 6 months ago

CBSE > Class 11 > Physics

2 answers

Anjan Karthi 1 year, 6 months ago

If you are asking vector or cross product, it will be vectorically represented as (-4×3 + 5×1)i - (3×3 + -2×5)j + (3×1 + -4×-2)k = -7i + j - 5k and it's magnitude will be √(7^2 + 1^2 + 5^2) = √(49 + 1 + 25) = √75 = 5√3. //

Anjan Karthi 1 year, 6 months ago

If you are asking the scalar or dot product, it will be of magnitude 3i.-2i + 1j.-4j + 5k.3k = 3(-2) + 1(-4) + 5(3) = -6 - 4 + 15 = 5 units// and direction will be cos x = A.B / magnitude of A × magnitude of B = 5 / √(3^2 + 4^2 + 5^2) × √(2^2 + 1^2 + 3^2) = 5 / √50 × √14 = 5 / √700 = 5/10√7 = 1/2√7.//

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