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A circle touches all four sides of a quadrilateral abcd with ab =6 cm bc=7cm and cd =4cm find ad

Posted by Harman Khehra 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Given, a circle touches all the four sides of a quadrilateral ABCD whose sides are AB = 6 cm, BC = 9 cm and CD = 8 cm.

If a circle touches all the four sides of quadrilateral ABCD, then
AB + CD = AD + BC
{tex}\therefore{/tex} 6 + 8 = AD + 9
{tex}\Rightarrow{/tex} 14 = AD + 9
{tex}\Rightarrow{/tex} 14-9 = AD
{tex}\Rightarrow{/tex} AD = 5 cm

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CBSE > Class 10 > Mathematics