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One side of a right triangle …

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One side of a right triangle measure 126 m and the difference in lengths of its hypotenuse and other is 42 m find the major of its 2 unknown slides and calculate its area verify the result using herons formula

Posted by Aishwarya Mohanty 7 years, 6 months ago

CBSE > Class 09 > Mathematics

1 answers

Rajeev Malhotra 7 years, 6 months ago

Let h= 126m and base = b m and Hypotenuse = h m

By pythagorous therem, we have h² = b² + (126)²

h² -b² = (126)²

(h+b)(h-b) = (126)²

It is given that h-b = 42 m

(h+b)*42= 126*126

h+b = 126*126/42

h+b= 3*126 = 378.....(1)

h-b = 42.....(2)

Adding eq(1) and (2), we get

2h= 420

h = 420/2=210m

Now h-b= 42

210-b =42

b= 210-42= 168m

Area = b*h/2

A= 168*126/2

A= 10584 m²

a=126m ,b=168m and c= 210m

s= a+b+c/2 = 126+168+210/2 = 504/2=252m

A = √s(s-a)(s-b)(s-c)

A= √252.(252-126)(252-168)(252-210)

A= √252*126*84*42

A= 10584m²

1Thank You

ANSWER

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