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Find the area of a triangle two sides of which are 18 cm 10 cm and the perimeter is 42 CM

Posted by Nilesh Singh Tanwar 1 year, 4 months ago

CBSE > Class 09 > Mathematics

1 answers

Omsri Dutta 1 year, 4 months ago

Another side = 42-(18+10)=42-28=14 S=42/2=21 Area = root over[ s(s-a)(s-a)(s-a) =root over[ 21(21-18)(21-10)(21-14) = root over[ 21×3×11×7] =root over[3×7×11×7×3] =21root11 cm²

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