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Solve the equation 2x-3y+11=0 and 3x+2y-3=0 …

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Solve the equation 2x-3y+11=0 and 3x+2y-3=0 by substitution method
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2x-3y+11=0,_eq(1), ,3x+2y-3=0,eq(2), 👇 X=-11+3y/2 _eq (3). From eq (2) 3(-11+3y/2)+2y-3=0. -33+9y/2+2y-3=0. -33+9y+4y-6=0×2. -33+13y-6=0. -39+13y=0. 13y=39. y=39/13. So, y=3. From EQ (3). X=-11+3(3)/2 X=-11+9/2. X=-2/2. X=-1👈and 😇
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