No products in the cart.

Two point charges of 12ûC and …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Two point charges of 12ûC and 8ûC are 10cm apart. The work done in bringing them 4cm close is=?
  • 1 answers

Deepak Meena 1 year, 8 months ago

We can use the formula for electrostatic potential energy to calculate the work done in bringing the two point charges closer. The formula for electrostatic potential energy is: U = k*q1*q2/r where U is the electrostatic potential energy, k is Coulomb's constant (= 9 x 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the charges in Coulombs, and r is the distance between the charges in meters. Initially, the charges are 10 cm = 0.1 m apart, so the initial distance r1 is 0.1 m. The final distance r2 when the charges are 4 cm = 0.04m apart. The magnitudes of the charges are q1 = 12 uC = 12 x 10^-6 C, and q2 = 8 uC = 8 x 10^-6 C. Using the formula and plugging in the values, we get: U1 = k*q1*q2/r1 = (9 x 10^9 Nm^2/C^2)(12 x 10^-6 C)(8 x 10^-6 C)/(0.1 m) ≈ 8.64 x 10^-5 J U2 = k*q1*q2/r2 = (9 x 10^9 Nm^2/C^2)(12 x 10^-6 C)(8 x 10^-6 C)/(0.04 m) ≈ 3.456 x 10^-4 J The change in electric potential energy ΔU is U2 - U1 = 2.594 x 10^-4 J. Therefore, the work done in bringing the charges 4cm closer is 2.594 x 10^-4 Joules.
http://mycbseguide.com/examin8/

Related Questions

Derivation of ohm's law class 12
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App