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Find the modulus (1-i/1+i)^100

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Find the modulus (1-i/1+i)^100

    • Posted by Gunjan Kashyap 1 year, 5 months ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Aditi Tiwari 1 year, 5 months ago

    √1 =1 hence modulus of (1-i/1+i)¹⁰⁰ is 1

    0Thank You

    Aditi Tiwari 1 year, 5 months ago

    (1-i/1+i)¹⁰⁰ Multiple with conjugate of denominator =(1-i*1-i/1+i*1-i)¹⁰⁰ =(1-i-i+i²/1-(i)²)¹⁰⁰ =(1-2i+(-1)/1-(-1))¹⁰⁰ =(-2i/2)¹⁰⁰ =(-i)¹⁰⁰ =(-i)⁴*²⁵+⁰ =(1)¹⁰⁰ =1 In complex form =1+0i |z|= √1²+0² |z|=√1

    0Thank You

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