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In mixture having 40g NaOH and …

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In mixture having 40g NaOH and 54g H2O find the mole fraction of mixture

Posted by Shivangi Arya 1 year, 6 months ago

CBSE > Class 12 > Chemistry

3 answers

Arpit Agnihotri 1 year, 5 months ago

total weight of solution(NaOH+H20) = 40+54 = 94 mole = mass/molar mass the molar mass of Na =40; O =16;H=1 mole fraction = mole of substance to be founded/mole fraction of solution now, mole fraction of NaOH = moles of NaOH/ (Mole of NaOH+Mole of H2O) = (40/40)/[(40/40)+(54/1*2+16*1)] = 1/[1+3] = 1/4 so, mole fraction of NaOH in the solution = 1/4 mole fraction ( solute+solvent) = 1 therefore mole fraction of H2O = 1-(1/4) mole fraction of H2O=3/4

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Rohit 1 year, 6 months ago

1/4

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Anshul Pratap Singh 1 year, 6 months ago

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