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Prove that √5 is irrational number.

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Prove that √5 is irrational number.
  • 3 answers

Kaushik Krishna 1 year, 6 months ago

Let √5 a rational number Where √5=a/b and a and b are co primes and b not equal to 0 Square them 5=a square / b square Cross multiply 5b square is equal to a square B is a factor of a B is also a factor of a square Now take A is equal to 5 c Square them A square is equal to 25 c square We know that a square is equal to 5 b square So now 5 b square is equal to 25 c square Simplify them We get b square is equal to 5 c square Now 5 is a factor of b square and b It contradict to our assumption that a and b are co primes Hence our assumption is wrong Therefore √5 is an irrational number Hence proved

Sureksha Sp 1 year, 6 months ago

Let √5 a rational number Where √5=a/b and a and b are co primes and b not equal to 0 Square them 5=a square / b square Cross multiply 5b square is equal to a square B is a factor of a B is also a factor of a square Now take A is equal to 5 c Square them A square is equal to 25 c square We know that a square is equal to 5 b square So now 5 b square is equal to 25 c square Simplify them We get b square is equal to 5 c square Now 5 is a factor of b square and b It contradict to our assumption that a and b are co primes Hence our assumption is wrong Therefore √5 is an irrational number Hence proved

Joshi Priya Dharmeshkumar 1 year, 6 months ago

Let √5 =a/b (where a/b is an rational number where a/b are co-primes) Squaring both the sides 5 = a2/b2 5b2 = a2 ---1 Thus 5 divides a2 , 5 divides a Now take any other integer as c such that a=5c squaring both the sides a2=25c2 --- 2 put a value from eq-1 into eq-2 5 b2 =25 c 2 b2=5c2 5 divides b2 and 5 divide b We let a&b are co-primes but here we are getting 5 as a factor of both a &b. So our prediction that a&b are co-primes is wrong Thus ✓5 is an Irrational number.
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