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Find sqaure root of 1+i

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Find sqaure root of 1+i
  • 2 answers

Jiyaaaaaaaaaa Sood 1 year, 6 months ago

Let tye square root of 1+i =root over 1+i Root over 1+i=x+iy By Squaring both sides We get , 1+i=(x+iy)² 1+i=x²+y²i²+2xyi As we know that i²=-1 So,, 1+i=x²-y²+2xyi Now compare real part and imaginary part on both sides... 1=x²-y²----1 equation 1=2xy------2equatiin We know a identwe says that (x²+y²)²=(x²-y²)²+(2xy)² Now put the values in this identity On adding and subtracting the above equations , we get ∴x2=22​+1​ and y2=22​−1​. ∴x=±22​+1​​andy=±22​−1​​ So, by equation (1), 1−i​=22​+1​​−i22​−1​​ Ans: 1

Aryan Choudhary 1 year, 6 months ago

Bjkkikgg
http://mycbseguide.com/examin8/

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