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2.5 g of ethanoic acid is …

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2.5 g of ethanoic acid is dissolved in 75g of benzene. Calculate molality of solution.

Posted by Gunjan Sharma 12Th 1 year, 7 months ago

CBSE > Class 12 > Chemistry

1 answers

Anjan Karthi 1 year, 7 months ago

m = Wb × 1000 / Wa × Mb = 2.5 × 1000 / 60 × 75 = 2500 / 4500 = 0.55 mol/kg

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