5 chairs and 4 tables together …

Cost of all chairs - 2800 Cost of all tables - 2800

Answer - Let the cost of 1 chair be x and 1 table be y Therefore, 5x + 4y = ₹5600 -----(1) And, 4x + 3y = ₹4340 -----(2) 4 So, We use elimination method. Multiplying Equation (1) by 3 & Multiplying Equation (2) by 4 Then Equation (1) will become 15x + 12y = ₹16800 ----(3) And, Second Equation will become 16x + 12y = ₹17360 ---(4) Then, to eliminate y we will subtract Equation (4) from Equation (3) i.e. - x = - 560 Therefore, x = ₹560 ---(5) So, putting the value of Equation (5) in Equation (1) Then, 5x + 4y = ₹5600 5(560) + 4y = 5600 2800 + 4y = 5600 4y = 5600 - 2800 4y = 2800 y = 2800/4 y = ₹700 ------(6) By the Equation (5) & (6), We can say that the cost of a chair is ₹560 and the cost of a table is ₹700.

Let 1 chair be x. and let 1 table be y. According to question case1. 5x+4y=₹5600.(Equation1) Case2. 4x+3y=₹4340.(equation2) by 4 in equation 1 and byBy elimination method Multiply 5 in equation 2 and substract equation 1 and 2 , we get 5(4x+3y)=₹4340 20x+15y=₹