Determine the ratio in which the …
Determine the ratio in which the line 2x+y-4=0 divdes the line segment joining the points A(2,-2) and B (3, 7)
Posted by _Jass_ Mahey_ 6 months ago
- 2 answers
in the ratio m₁: m₂ is given by the Section Formula. P (x, y) = [(mx₂ + nx₁) / (m + n) , (my₂ + ny₁) / (m + n)] Let the given line 2x + y - 4 = 0 divide the line segment joining the points A(2, - 2) and B(3, 7) in a ratio k: 1 at point C. Coordinates of the point of divison C (x, y) = [(3k + 2) / (k + 1), (7k - 2) / (k + 1)] Hence, x = (3k + 2) / (k + 1), y = (7k - 2) / (k + 1) This point C also lies on 2x + y - 4 = 0 .....(1) By substituting the values of C(x, y) in Equation(1), 2[(3k + 2) / (k + 1)] + [(7k - 2) / (k + 1)] - 4 = 0 [6k + 4 + 7k - 2 - 4k - 4] / (k + 1) = 0 (By Cross multiplying & Transposing) 9k - 2 = 0 k = 2/9 Therefore, the ratio in which the line 2x + y - 4 = 0 divides the line segment joining the points A (2, 2) and B (3, 7) is 2:9 internally.
Rita was studying in class 9th C of St. Surya Public School, Mohali, New Delhi-110030. Once Ranjeet and his daughter Rita were returning after attending teachers' parent meeting at Rita's school. As the home of Ranjeet was close to the school so they were coming by walking. Rita asked her father, "Daddy how old are you?" Ranjeet said, "At present, sum of ages of both of us is 55 years and after 10 years my age will be double of you."
Posted by Son Sammy 1 day, 17 hours ago
- 1 answers