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Exercise 1.1 q 2

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Exercise 1.1 q 2

    • Posted by Sharvan Verma 1 year, 8 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    _Jass_ Mahey_ 1 year, 8 months ago

    Let 'a' be a postive odd integer also. Let 'q' be quotient and 'r' be the remainder after dividing by six. Then a=6q+r, where 0<r<6. Postive integer are 1,2,3,4,5 a=6q+0, 6q+1, 6q+2, 6q+3, 6q+4, 6q+5. But a=6q, 6q+2 and 6q+4 are even. When a is add it is the form 6q+1, 6q+3, 6q+5 for some integer q. .°. Hence proved...

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