A man has certain notes of …
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Preeti Dabral 2 years, 7 months ago
Let’s consider the number of 20 rupee notes to be x
And the number of 5 rupee notes be y
Then, according to the given conditions, we have
20x+5y=380 … (i) and
5x+20y=380−60
⇒5x+20y=320 … (ii)
Now, multiplying eq(i) by 4 and subtracting with eq(ii), we get
(80x+20y)−(5x+20y)=1520−320
⇒75x=1200
{tex}\begin{aligned} & \Rightarrow \mathrm{x}=\frac{1200}{75} \\ & \Rightarrow \mathrm{x}=16 \end{aligned}{/tex}
On substituting the value of x in eq(i), we get
20(16)+5y=380
⇒320+5y=380
⇒5y=380−320=60
{tex}\begin{aligned} & \Rightarrow y=\frac{60}{5} \\ & \Rightarrow y=12 \end{aligned}{/tex}
Therefore,
The number of 20 rupee notes =16 and
The number of 5 rupee notes =12
0Thank You