Let A and B be two …
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Preeti Dabral 2 years, 9 months ago
Solution is given below:
{tex}\begin{aligned} & n(A \cup B)=n(A)+n(B)-n(A \cap B) \\ & n(B)=42-20+4=26 \\ & n(A-B)=n(A)-n(A \cap B)=20-4=16 \\ & n(B-A)=n(B)-n(A \cap B)=26-4=22 \end{aligned}{/tex}
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