How much potassium chlorate should be …
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Preeti Dabral 2 months, 3 weeks ago
When potassium chlorate is heated, then following reaction takes place:
2KClO3 {tex}\rightarrow{/tex} 2KCl + 3O2
Molecular mass of 1mol KClO3 = 39 + 35.5 + 3 {tex}\times{/tex}16= 122.5 g
Molecular mass of 2 mols of KClO3 = 2{tex}\times{/tex}122.5 g =245 g
Volume occupied by 3 mol of oxygen = 3{tex}\times{/tex}22.4L = 67.5 L
Therefore, 67.2L of oxygen is produced from 245g of KClO3
2.24L of oxygen is produced from = {tex}\frac { 245 } { 67.2 } \times 2.24{/tex}= 8.17g of KClO3
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