(SiH3)3N is weaker base than (CH3)3N …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Deepak Kumar 8 years, 11 months ago
- 1 answers
Test
Related Questions
Posted by Bhavishaya 2009 1 year, 5 months ago
- 0 answers
Posted by Priya Dharshini B 1 year, 5 months ago
- 4 answers
Posted by Karan Kumar Mohanta 1 year, 4 months ago
- 1 answers
Posted by Prity Rani Mishra 1 year, 5 months ago
- 0 answers
Posted by Shikhar Manav 1 year, 5 months ago
- 0 answers
Posted by Kashish Baisla 9 months, 1 week ago
- 1 answers
Posted by Roshni Gupta 1 year, 5 months ago
- 0 answers
Posted by Mahi Sharma 1 year, 5 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Bindu Agarwal 8 years, 11 months ago
It is due to backbonding between empty 3d orbital of Si and filled 2p orbitals of N which is not possible in the case of (CH3)3N as no vacant d orbital is present.
0Thank You