Find the equation of a line …
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Preeti Dabral 2 years, 7 months ago
We are given that, p = 4 and ω = 150
Now, {tex}\cos 15^{\circ}=\frac{\sqrt{3}+1}{2 \sqrt{2}}{/tex}
and {tex}\sin 15^{\circ}=\frac{\sqrt{3}-1}{2 \sqrt{2}}{/tex}
The equation of the line is x cos ω + y sin ω = p
{tex}x \cos 15^{\circ}+y \sin 15^{\circ}{/tex}
or {tex}\frac{\sqrt{3}+1}{2 \sqrt{2}} x+\frac{\sqrt{3}-1}{2 \sqrt{2}} y=4{/tex}
or {tex}(\sqrt{3}+1) x+(\sqrt{3}-1) y=8 \sqrt{2}{/tex}
This is the required equation.
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