In fig., Ab||CD angle APQ= 50°, …
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Preeti Dabral 2 years, 1 month ago
We are given that AB∥CD,∠APQ=50∘ and ∠PRD = 127°
We need to find the value of x and y in the figure.
∠APQ = x = 50° (Alternate interior angles)
∠PRD = ∠APR = 127° (Alternate interior angles)
∠APR = ∠QPR + ∠APQ.
127° = y + 50°
⇒ y = 77°.
Therefore, we can conclude that x = 55° and y = 77°
Alternatively, 127° = y + x (because exterior angle is equal to the sum of interior opposite angles).
so, 127° = y + 50°
which gives, x = 50° and y = 77°
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