In fig., Ab||CD angle APQ= 50°, …
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Posted by Pushkar Gajbhiye 1 year, 7 months ago
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Preeti Dabral 1 year, 7 months ago
We are given that {tex}AB\parallel CD,\angle APQ = {50^\circ }{/tex} and {tex}\angle{/tex}PRD = 127°
We need to find the value of x and y in the figure.
{tex}\angle{/tex}APQ = x = 50° (Alternate interior angles)
{tex}\angle{/tex}PRD = {tex}\angle{/tex}APR = 127° (Alternate interior angles)
{tex}\angle{/tex}APR = {tex}\angle{/tex}QPR + {tex}\angle{/tex}APQ.
127° = y + 50°
{tex}\Rightarrow{/tex} y = 77°.
Therefore, we can conclude that x = 55° and y = 77°
Alternatively, 127° = y + x (because exterior angle is equal to the sum of interior opposite angles).
so, 127° = y + 50°
which gives, x = 50° and y = 77°
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