From a solid cylinder of hieght …
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Preeti Dabral 1 year, 9 months ago
Height of the cylinder (h) = 14 cm,
Base diameter = 7 cm
{tex}\Rightarrow{/tex} Radius of the base of the cylinder (r) = 3.5 cm
Volume of the cylinder = {tex}\pi r ^ { 2 } h{/tex}
= {tex}\frac { 22 } { 7 } \times 3.5 \times 3.5 \times 14{/tex}
= 22 {tex}\times{/tex}3.5 {tex}\times{/tex}3.5{tex}\times{/tex}14
= 539 cm3
Radius of the conical holes (r1) = 2.1 cm,
Height of the conical holes (h1) = 4 cm,
volume of the conical hole {tex}= \frac { 1 } { 3 } \pi r _ { 1 } ^ { 2 } h _ { 1 }{/tex}
{tex}= \frac { 1 } { 3 } \times \frac { 22 } { 7 } \times 2.1 \times 2.1 \times 4{/tex}
= 18.48 cm3
Volume of the two conical hole = 2 {tex}\times{/tex}18.48
= 36.96 cm3
Volume of the remaining solid = Volume of the cylinder - Volume of two conical hole
= 539 - 36.96
= 502.04 cm3
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