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D is midpoint on the side …

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D is midpoint on the side bc of triangle ABC such that ADC=bac show that ca2=cb.cd
  • 2 answers

K. Hema 1 year, 9 months ago

Given, D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. In ΔADC and ΔBAC, ∠ADC = ∠BAC (Already given) ∠ACD = ∠BCA (Common angles) ∴ ΔADC ~ ΔBAC (AA similarity criterion) We know that corresponding sides of similar triangles are in proportion. ∴ ����=����CBCA​=CACD​ ⇒ CA2 = CB.CD. Hence, proved.

Abell Thankachan 1 year, 9 months ago

I don't know
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