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SinA+cosecA2 +cosA + secA2 =7+tan2A+ cot2A

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SinA+cosecA2 +cosA + secA2 =7+tan2A+ cot2A

Posted by Aryan Sharma 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Renuka Sahoo 2 years, 2 months ago

=Sin²A+Cosec²A+2SinA.CosecA+Cos²A+Sec²A+2CosA.SecA =Sin²A+Cosec²A+Cos²A+Sec²A+4 =Sin²A+Cos²A+4+Cosec²A+Sec²A =1+4+Cosec²A+Sec²A =5+1+Cot²A+1+Tan²A =7+tan²A+Cot²A

1Thank You

V R 2 years, 2 months ago

That is a wrong questions... Right questions is (SinA+cosecA)^2 +(cosA + secA)^2=(7+tan2A+ cot2A)

1Thank You

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CBSE > Class 10 > Mathematics