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SinA+cosecA2 +cosA + secA2 =7+tan2A+ cot2A

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SinA+cosecA2 +cosA + secA2 =7+tan2A+ cot2A

    • Posted by Aryan Sharma 1 year, 9 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Renuka Sahoo 1 year, 9 months ago

    =Sin²A+Cosec²A+2SinA.CosecA+Cos²A+Sec²A+2CosA.SecA =Sin²A+Cosec²A+Cos²A+Sec²A+4 =Sin²A+Cos²A+4+Cosec²A+Sec²A =1+4+Cosec²A+Sec²A =5+1+Cot²A+1+Tan²A =7+tan²A+Cot²A

    1Thank You

    V R 1 year, 9 months ago

    That is a wrong questions... Right questions is (SinA+cosecA)^2 +(cosA + secA)^2=(7+tan2A+ cot2A)

    1Thank You

    ANSWER
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