If the sum of first m …
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Preeti Dabral 2 years, 1 month ago
Let a be the first term and d be the com m on difference of the given A.P. Then,
Sm = Sn
⇒m2{2a + (m - 1) d} = n2{2a + (n - 1) d}
⇒ 2a(m - n) + {m(m - 1) - n(n - 1)} d = 0
⇒ 2a(m - n) + [(m2 - n2) - (m - n)d = 0
⇒ (m - n){2a + (m + n - 1)d = 0
⇒ 2a + (m + n - 1)d = 0 [∵ m - n ≠ 0] ...(i)
∴ Sm+n = m+n2 {2a + (m + n - 1) d} = m+n2× 0 = 0 [Using (i)]
Hence proved on basis of above equation.
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