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Prove that o.85×0.85×0.85+0.15×0.15×0.15÷0.85×0.85-0.85×0.15+0.15×0.15=1

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Prove that o.85×0.85×0.85+0.15×0.15×0.15÷0.85×0.85-0.85×0.15+0.15×0.15=1

    • Posted by Divyansh Goyal 2 years, 3 months ago

    CBSE > Class 09 > Mathematics
    • 3 answers

    Smriti Gupta 2 years, 3 months ago

    LHS:0.85×0.85×0.85+0.15×0.15×0.150.85×0.85−0.85×0.15+0.15×0.15 We know a3+b3=(a+b)(a2+b2−ab) Here a=0.85,b=0.15 (0.85+0.15)(0.852−0.85×0.15+0.152)=(0.85+0.15)(0.852−0.85×0.15+0.152)(0.852−0.85×0.15+0.152)=0.85+0.15=1 Thus, LHS = RHS

    1Thank You

    Koyna Tulshyan 2 years, 3 months ago

    ANSWER: LHS:0.85×0.85×0.85+0.15×0.15×0.150.85×0.85−0.85×0.15+0.15×0.15 We know a3+b3=(a+b)(a2+b2−ab) Here a=0.85,b=0.15 (0.85+0.15)(0.852−0.85×0.15+0.152)=(0.85+0.15)(0.852−0.85×0.15+0.152)(0.852−0.85×0.15+0.152)=0.85+0.15=1 Thus, LHS = RHS

    0Thank You

    Avantika Mishra 2 years, 3 months ago

    Prove that

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