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Prove that o.85×0.85×0.85+0.15×0.15×0.15÷0.85×0.85-0.85×0.15+0.15×0.15=1

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Prove that o.85×0.85×0.85+0.15×0.15×0.15÷0.85×0.85-0.85×0.15+0.15×0.15=1

Posted by Divyansh Goyal 2 years, 4 months ago

CBSE > Class 09 > Mathematics

3 answers

Smriti Gupta 2 years, 4 months ago

LHS:0.85×0.85×0.85+0.15×0.15×0.150.85×0.85−0.85×0.15+0.15×0.15 We know a3+b3=(a+b)(a2+b2−ab) Here a=0.85,b=0.15 (0.85+0.15)(0.852−0.85×0.15+0.152)=(0.85+0.15)(0.852−0.85×0.15+0.152)(0.852−0.85×0.15+0.152)=0.85+0.15=1 Thus, LHS = RHS

1Thank You

Koyna Tulshyan 2 years, 4 months ago

ANSWER: LHS:0.85×0.85×0.85+0.15×0.15×0.150.85×0.85−0.85×0.15+0.15×0.15 We know a3+b3=(a+b)(a2+b2−ab) Here a=0.85,b=0.15 (0.85+0.15)(0.852−0.85×0.15+0.152)=(0.85+0.15)(0.852−0.85×0.15+0.152)(0.852−0.85×0.15+0.152)=0.85+0.15=1 Thus, LHS = RHS

0Thank You

Avantika Mishra 2 years, 4 months ago

Prove that

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