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(102)cube

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(102)cube
  • 3 answers

Smriti Gupta 1 year, 8 months ago

1061208

Shikhar Sahu 1 year, 8 months ago

(102)³ can be written as (100+2)³ As we know identity of (x+y)³=x³+y³+3xy(x+y) So, (100+2)³=100³+2³+3*100*2(100+2) 1000000+8+60000+1200 1061208 ans

Puskar Choudhury 1 year, 8 months ago

1061208
http://mycbseguide.com/examin8/

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