1+secA=sin²a SecA 1-cosA
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Daksh Vijay 2 years, 9 months ago
- 1 answers
Related Questions
Posted by Kanika . 2 months, 4 weeks ago
- 1 answers
Posted by Hari Anand 4 months, 4 weeks ago
- 0 answers
Posted by Parinith Gowda Ms 2 months ago
- 0 answers
Posted by Parinith Gowda Ms 2 months ago
- 1 answers
Posted by Lakshay Kumar 11 months, 2 weeks ago
- 0 answers
Posted by Vanshika Bhatnagar 1 year, 3 months ago
- 2 answers
Posted by Sahil Sahil 1 year, 3 months ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Preeti Dabral 2 years, 9 months ago
{tex}\begin{aligned} & \text { To prove : } \frac{1+\sec \mathrm{A}}{\sec \mathrm{A}}=\frac{\sec ^{12} \mathrm{~A}}{1-\cos \mathrm{A}} \\ & \text { LHS } \frac{1+\sec \mathrm{A}}{\sec \mathrm{A}}=\frac{1+\frac{1}{\cos \mathrm{A}}}{\frac{1}{\cos \mathrm{A}}} \\ & =\frac{\frac{\cos \mathrm{A}+1}{\cos \mathrm{A}}}{\frac{1}{\cos \mathrm{A}}} \\ & =\frac{\cos \mathrm{A}+1}{\cos \mathrm{A}} \times \frac{\cos \mathrm{A}}{1} \\ & =1+\cos \mathrm{A} \\ & =1+\cos \mathrm{A} \times \frac{1-\cos \mathrm{A}}{1-\cos \mathrm{A}} \\ & =\frac{(1)^2-(\cos \mathrm{A})^2}{1-\cos \mathrm{A}} \\ & =\frac{1-\cos 2 \mathrm{~A}}{1-\cos \mathrm{A}} \end{aligned}{/tex}
{tex}\begin{aligned} & =\frac{\sin ^2 \mathrm{~A}}{1-\cos \mathrm{A}} \\ & =\mathrm{RHS} \end{aligned}{/tex}
1Thank You