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If Q(0,1)is equidistant from p(5,-3)R(x,6) find …

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If Q(0,1)is equidistant from p(5,-3)R(x,6) find the value ofx.also find the distance QR and pR

Posted by Rohit Thakur 1 year, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Suhani Verma 1 year, 10 months ago

Qp= √( X-x )² + (Y-y)² = √(5-0)² + (-3-1)² = √ (5)² + (-4)² = √ 25+16 = √ 41 QR= √ (X-x)² + (Y-y)² = √ (x-0)² + (6-1)² = √ (x)² + (5)² = √ x² + 25 Qp =QR √41 = √x² +25 Both side squaring (√41)² = (√x²+25) 41 = x² + 25 41- 25=x² 16 = x² 4 = x Distance between, QR=√( 4-0)² + (6-1)² = √(4)² + (5)² =√16+25 =√41 PR=√(5-4)² + (-3-6)² =√(1)² + (-9)² =√ 1+81 =√82

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