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Q.24 Prove that angles opposite to …

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Q.24 Prove that angles opposite to equal sides of a triangle are equal 
  • 1 answers

Preeti Dabral 1 year, 10 months ago

ABC is a given triangle with, AB=AC.

To prove: Angle opposite to AB= Angle
opposite to AC (i.e) ∠C=∠B

Construction: Draw AD perpendicular to BC
∴∠ADB=∠ADC=90o

Proof: 
Consider △ABD and △ACD

AD is common

AB=AC

∴∠ADB=∠ADC=90o

Hence ∠ABD=∠ACD
∠ABC=∠ACB
∠B=∠C. Hence the proof
This is known as Isosceles triangle theorem

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